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Problem 1 - Entrance Test

For a galvanic cell with Zn | Zn²⁺ (1M) || Cu²⁺ (0.1M) | Cu, calculate the cell potential. Given: E°(Zn²+/Zn) = -0.762 V, E°(Cu²+/Cu) = +0.34 V. (Assume 298 K)

Correct: A

E°cell = 0.34 - (-0.762) = 1.102 V. Apply Nernst equation: E = E° - (0.0592/2) log([Zn²⁺]/[Cu²⁺]) = 1.102 - (0.0592/2) log(1/0.1) = 1.102 - 0.0296 = 1.07 V.