In a right-angled triangle ABC, right-angled at B, if AB = 8 cm and BC = 6 cm, what is the value of sec C?
Correct: A
First, find the hypotenuse AC using the Pythagoras theorem: AC² = AB² + BC² = 8² + 6² = 64 + 36 = 100. So, AC = √100 = 10 cm. For angle C, the Opposite side is AB = 8 cm, the Adjacent side is BC = 6 cm, and the Hypotenuse is AC = 10 cm. The definition of sec C is Hypotenuse / Adjacent = AC / BC = 10 / 6.