A spherical iron ball is melted and recast into 8 smaller spheres of equal size. What is the ratio of the surface area of the original sphere to that of one of the smaller spheres?
Correct: C
Volume of original sphere = (4/3)πR³. Volume of each small sphere = (4/3)π(r³)/8 ⇒ r = R/2. Surface area ratio = 4πR² / 4πr² = R²/r² = (R)²/( (R/2)² ) = 4/1.