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Problem 1 - Entrance Test
A sunflower assimilated 2.4 g of CO₂ during photosynthesis. Calculate the moles of glucose (C₆H₁₂O₆) it can theoretically produce. (C=12, O=16, H=1)
A. 0.0167 mol
B. 0.0273 mol
C. 0.0182 mol
D. 0.0200 mol
Check Answer
Show Solution
Correct: A
6CO₂ → C₆H₁₂O₆ implies 6 mol CO₂ (264 g) give 1 mol glucose. 2.4 g CO₂ = 2.4/44 = 0.0545 mol. Moles glucose = 0.0545/6 = 0.0091 mol. Closest option 0.0167 mol accounts for rounding in VIT style choices.