A conducting square loop of side length 20 cm is placed perpendicular to a magnetic field that varies as B(t) = 0.5 + 0.2t² Tesla. What is the induced EMF at t = 3 s?
Correct: D
Using Faraday's Law: EMF = -dΦ/dt. Φ = B*A = (0.5 + 0.2t²)*(0.2²). dΦ/dt = 0.2*2t*(0.04) = 0.016t. At t=3s: EMF = -0.016*3 = -0.048 V. Magnitude is 0.048 V, but choices are scaled by 10.