In a population in Hardy-Weinberg equilibrium, 4% of individuals show a recessive trait. What is the frequency of the dominant allele?
Correct: B
Using the Hardy-Weinberg equation (q² = 0.04 → q = 0.2). The dominant allele frequency is 1 - q = 0.8 → p² + 2pq = 0.8² + 2*(0.8*0.2) = 0.64 + 0.32 = 0.96. However, the question asks for the dominant allele frequency directly, which is 0.8.