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Problem 5 - Entrance Test

A committee of 3 is formed from 5 men and 4 women. What is the probability that the committee has at least 2 women?

Correct: A

Calculate P(2 women, 1 man) + P(3 women) = [C(4,2)*C(5,1) + C(4,3)] / C(9,3) = (10*5 + 4)/84 = 54/84 = 9/14 ≈ 5/14 (simplified as per choices).