In a triangle ABC, D and E are the points on AB and AC respectively such that BC = DE. Find the ratio of the areas of triangle ABC and triangle DBE.
Correct: A
Draw a line through D parallel to BC and another line through E parallel to BC to meet the first line at F. Then triangle DBE and triangle ABC are similar. Therefore the ratio of their areas is (DE/BC)^2. But DE = BC, so the ratio of the areas of triangle ABC and triangle DBE is (BC/BC)^2 = 1.