Find the equation of the line which passes through (1, 2) and is perpendicular to the line 3x + 2y = 5.
Correct: C
The slope of the given line is -A/B = -3/2. So the slope of the required line is 2/3 (since the slopes of two perpendicular lines are negative reciprocals of each other). Using point-slope form, y - 2 = (2/3)(x - 1). Simplifying gives 3y - 6 = 2x - 2, so 2x - 3y + 4 = 0.