A 2 kg object falls freely 10 m under gravity. What is its average power dissipated against air resistance if terminal speed is 15 m/s at 10 m?
Correct: D
At terminal speed, power P = F × v = mg × v. P = 2×10×15 = 300 W. Since work is done over 10 m, average power = total work (mgh = 200 J) over time (10/15 ≈ 0.667 s) ≈ 300 W. Correct answer is not listed; review for inconsistency.