What is the perimeter of a regular hexagon inscribed in a circle with a radius of 8 units?
Correct: C
When a regular hexagon is inscribed in a circle, the side length of the hexagon is equal to the radius of the circle.
This is because a regular hexagon can be divided into six equilateral triangles, each with vertices at the center of the circle and two adjacent vertices of the hexagon. The sides of these equilateral triangles are all equal to the radius.
Given the radius (r) = 8 units.
The side length (s) of the regular hexagon = r = 8 units.
A hexagon has 6 equal sides.
The perimeter of the hexagon = 6 * s = 6 * 8 = 48 units.