What is the equation of a circle with center (2, 3) and radius 4?
Correct: A
The general equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h, k) is the center and r is the radius. Given the center (2, 3) and radius 4, we substitute h=2, k=3, and r=4 into the equation, yielding (x-2)^2 + (y-3)^2 = 4^2, which simplifies to (x-2)^2 + (y-3)^2 = 16.