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Problem 5 - Entrance Test

The de Broglie wavelength of a particle with mass 'm' and kinetic energy 'E' is given by:

Correct: A

De Broglie wavelength (λ) = h/p, where p is momentum. Kinetic energy (E) = p^2 / 2m, so p = √(2mE). Therefore, λ = h/√(2mE).