What is the standard electrode potential for the half-cell reaction: Zn2+(aq) + 2e- → Zn(s), given that ΔG° = -212.3 kJ/mol (F = 96500 C/mol)?
Correct: B
ΔG° = -nFE°, where n is the number of moles of electrons transferred, F is the Faraday constant, and E° is the standard electrode potential. -212300 J/mol = -2 * 96500 C/mol * E°. Solving for E°, we get E° ≈ -1.10 V.