What is the value of (2^0 + 2^1 + 2^2 + ... + 2^10) ?
Correct: A
This is a geometric progression where first term(a) = 2^0 = 1, common ratio(r) = 2 and number of terms(n) = 11. The sum of n terms of a G.P. is given by Sn = a(r^n - 1)/(r - 1). So, (2^0 + 2^1 + 2^2 + ... + 2^10) = 1*(2^11 - 1)/(2 - 1) = 2^11 - 1 = 2048 - 1 = 2047.