What is the value of (5^0 + 5^1 + 5^2 + ... + 5^10) ?
Correct: D
This is a geometric progression where first term(a) = 5^0 = 1, common ratio(r) = 5 and number of terms(n) = 11. The sum of n terms of a G.P. is given by Sn = a(r^n - 1)/(r - 1). So, (5^0 + 5^1 + 5^2 + ... + 5^10) = 1*(5^11 - 1)/(5 - 1) = (5^11 - 1)/4.