A capacitor of capacitance 100 μF is connected to a 12 V battery. What is the energy stored in the capacitor?
Correct: A
The energy stored in the capacitor is given by E = 0.5CV^2, where C is the capacitance and V is the voltage. Substituting the given values, we get E = 0.5 * (100 * 10^-6 F) * (12 V)^2 = 0.072 J, which is closest to 0.06 J.