A particle moves in a circular path with a constant speed of 5 m/s. If the radius of the circular path is 2 m, what is the magnitude of the acceleration of the particle?
Correct: D
The acceleration of the particle is given by a = v^2 / r, where v is the speed and r is the radius of the circular path. Substituting the given values, we get a = (5 m/s)^2 / (2 m) = 12.5 m/s^2.