A battery of emf 2 V and internal resistance 0.5 ohms is connected to a resistance of 2 ohms. What is the current in the circuit?
Correct: B
The current in the circuit is given by the equation I = E / (R + r), where I is the current, E is the emf, R is the external resistance, and r is the internal resistance. Substituting the given values, we get I = (2 V) / (2 ohms + 0.5 ohms) = (2 V) / (2.5 ohms) = 0.8 A, which is closest to 1 A among the given options.