A circuit has a resistance of 10 ohms and an inductance of 1 H. If a voltage of 10 V is applied to the circuit, what is the current in the circuit after 2 s?
Correct: B
The current in the circuit is given by the equation I = V * (1 - e^(-t / τ)), where I is the current, V is the voltage, t is the time, and τ is the time constant. The time constant is given by τ = L / R, where L is the inductance and R is the resistance. Substituting the given values, we get τ = (1 H) / (10 ohms) = 0.1 s. Then I = (10 V / 10 ohms) * (1 - e^(-2 / 0.1)) = 1 * (1 - e^(-20)) = 1 * (1 - 2.06 * 10^(-9)) = 1 A.