A current of 2 A flows through a resistor of resistance 5 ohms. What is the power dissipated in the resistor?
Correct: C
The power dissipated in the resistor is given by P = I^2 * R, where I is the current and R is the resistance. Substituting the given values, we get P = (2 A)^2 * (5 ohms) = 4 * 5 = 20 W.