What is the equation of the axis of symmetry of the parabola y = x^2 - 4x + 3?
Correct: B
The axis of symmetry of a parabola given by y = ax^2 + bx + c is given by the equation x = -b / (2a). For the given parabola y = x^2 - 4x + 3, a = 1 and b = -4. So, the equation of the axis of symmetry is x = -(-4) / (2*1) = 4 / 2 = 2.