What is the equation of the perpendicular bisector of the line segment joining the points (2, 3) and (6, 7)?
Correct: C
The midpoint of the line segment joining (2, 3) and (6, 7) is ((2+6)/2, (3+7)/2) = (4, 5). The slope of the line joining the two points is (7-3)/(6-2) = 4/4 = 1. The slope of the perpendicular line will be the negative reciprocal of 1, which is -1. The equation of the line passing through (4, 5) with a slope of -1 is y - 5 = -1(x - 4), which simplifies to y - 5 = -x + 4, and further to x + y - 9 = 0.