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Problem 6 - Entrance Test
Two resistors, R₁ and R₂, are connected in parallel. The equivalent resistance of the parallel combination is:
A. R₁R₂ / (R₁ + R₂)
B. R₁ + R₂
C. (R₁ + R₂) / R₁R₂
D. √(R₁² + R₂²)
Check Answer
Show Solution
Correct: A
For resistors in parallel, 1/R_eq = 1/R₁ + 1/R₂. Solving for R_eq gives R_eq = R₁R₂ / (R₁ + R₂).