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Problem 9 - Olympiad
The de-Broglie wavelength of an electron accelerated through 15 kV is closest to
A. 0.01 nm
B. 0.1 nm
C. 1 nm
D. 10 nm
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Correct: A
λ = h/p = 1.226/√V nm = 1.226/√15000 ≈ 0.01 nm.