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Problem 6 - Entrance Test

If f(x) = x^2 - 4x + 5, what is the value of f(x) when x = 2?

Correct: A

To find f(x) when x = 2, we substitute 2 for x in the function f(x) = x^2 - 4x + 5. So, f(2) = 2^2 - 4(2) + 5 = 4 - 8 + 5 = 1.