A box contains 5 red balls and 3 blue balls. What is the probability of drawing a red ball and then a blue ball, without replacement?
Correct: A
The total number of balls initially is 8 (5 red + 3 blue). The probability of drawing a red ball first is 5/8. After drawing a red ball without replacement, there are 7 balls left (4 red + 3 blue). The probability of drawing a blue ball next is 3/7. The probability of both events happening in sequence is found by multiplying the probabilities of the individual events: (5/8) * (3/7) = 15/56.